/*
Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".
*/

class Solution {
public:
    bool wordBreak(string s, unordered_set<string> &dict) {
        vector<bool> wordB(s.length() + 1, false);
        wordB[0] = true;
        for (int i = 0; i < s.length(); i++) {
            for (int j = 0; j <= i; j++) {
                if (wordB[j] && dict.find(s.substr(j, i - j + 1)) != dict.end()) {
                    wordB[i+1] = true;
                    break;
                }
            }
        }
        return wordB[s.length()];
    }
};
